245p^2-45=0

Solution for 245p^2-45=0 equation:

245p^2-45=0

a = 245; b = 0; c = -45;
Δ = b2-4ac
Δ = 02-4·245·(-45)
Δ = 44100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{44100}=210$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-210}{2*245}=\frac{-210}{490}
=-3/7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+210}{2*245}=\frac{210}{490}
=3/7
$